Air bags are activated when a severe impact causes a steel ball to compress a spring and electrically ignite a detonator cap. This causes sodium azide (NaN3) to decompose explosively according to the following reaction.
2 NaN3(s) 2 Na(s) + 3 N2(g)
What mass of NaN3(s) must be reacted in order to inflate an air bag to 76.5 L at STP?
find out the no of moles of NaN3 using following formula
PV = nRT formula
STP means P = 1 atm , T = 273K,
R = 0.0821 L atm/mol-K
n = no o fmoles, V is given 76.5 L
we need to calculate n
put all these values in the above equation
1 atm x 76.5 L = n x 0.0821 L-atm/mol-K x 273K
n = 76.5 L / 22.41
n = 3.413 moles
2 NaN3(s) -----> 2 Na(s) + 3 N2(g)
from this balanced equation moles of 2 moles of NaN3 required to produce 3 moles of N2
moles of NaN3 required = 2/3 x 3.413 = 2.3 moles
now we got the moles of NaN3
find out the mass using formula
no of moles = weight / molar mass
weight = moles of NaN3 x molar mass of NaN3
weight = 2.3 moles x 65 g/mole
= 147.9 grams
Get Answers For Free
Most questions answered within 1 hours.