Question

How much ammonia can be synthesized from 5.22 kg of H2 and 31.5 kg of N2 based on the following reaction:

3 H2(g) + N2(g) à 2 NH3(g)

(H2= 2.02 g/mol, N2= 28 g/mol, NH3 = 17.02 g/mol)

A.15.5 kg

B.29.3 kg

C.38.3 kg

D.65.9 kg

Answer 1

From the balanced chemical equation;

3 moles of H2 and 1 mole of N2 reacted to give 2 moles of NH3

no. of moles of H2 = 5.22 / 2.02 = 2.584 moles

no. of moles of N2 = 31.5 / 28 = 1.125 moles

no. of moles of H2 needed to react with 1.125 moles of N2 = 3 x 1.125 = 3.375 mole

actual moles of H2 present are less. So. limiting reagent is H2

So, the no. of moles of NH3 formed = (2/3) x 2.584 = 1.723 moles of NH3

Weight of NH3 formed = 1.723 x 17.02 = 29.3 kg

B.29.3 kg