a. What is the pH of a solution containing 0.2 M HA and 0.1 M A- ? Ka of HA is 0.002.
b.
What ratio of NaCHO2:HCHO2 would be required to make a buffer with pH 2.97 ?
Formic Acid, HCHO2 pKa = 3.74
a)
Ka = 2*10^-3
pKa = - log (Ka)
= - log(2*10^-3)
= 2.699
we have below equation to be used:
This is Henderson–Hasselbalch equation
pH = pKa + log {[conjugate base]/[acid]}
= 2.699+ log {0.1/0.2}
= 2.40
Answer: 2.40
b)
we have below equation to be used:
This is Henderson–Hasselbalch equation
pH = pKa + log {[conjugate base]/[acid]}
2.97 = 3.74+log {[NaCHO2]/[HCHO2]}
log {[NaCHO2]/[HCHO2]} = -0.77
[NaCHO2]/[HCHO2] = 0.170
Answer: 0.170
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