When the valve is opened , both the gase occupy both bulbs. thus the total volume = 3.0+ 4.0 = 7.0L
Now partial pressure of N2 after mixing
P1V1 = P2V2 at constant temperature
3.0L x 2.0 atm = P2 x 7.0L
Thus P2 of N2 = 6/7 = 0.8571 atm
Similarly partial pressure of O2 after mixing
P1V1 = P2V2 at constant temperature
4.0L x 3.0 atm = P2 x 7.0L
Thus P2 of N2 = 12/7 = 1.714 atm
Thus the total pressure after the valve is opened = PN2 + PO2 after mixing
= 0.8571 + 1.714 atm
= 2.5713 atm
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