How much ethylene glycol must be added to 1.1 L of water to keep it from freezing at -13 degreeF ? The Kf value is 1.86 degree C/molal. Explain how you determined your answers.
first convert F to 0C
- 13 degree F = -25 0C
now we have a relation
Tf = Kf x m
m = molality = (W /MW) (1000 / mass of solvent in g)
Tf = Kf x W x 1000 / MW x mass of solvent in g
W = Tf x MW x mass of solvent in g / Kf x 1000
Tf = 0 - (-25) = 25
MW = 62.07 g/mol
mass of solvent = 1.1 Kg = 1100 g (because density of water = 1.0 g/mL)
Kf = 1.860C / mol
W = 25 x 62.07 x 1.86 x 1000
W = 1551.75 / 1860
W = 0.83 g
mass of ethylene glycol required = 0.83 g
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