Question

How much heat in kJ is required to warm 10.0g of ice, initially at -10.0oC, to steam at 110.0oC? The heat capacity of ice is 2.09 J/goC and that of steam is 1.84 J/goC.

Answer #1

We require 2 type of heat, latent heat and sensible heat

Sensible heat (CP): heat change due to Temperature difference

Latent heat (LH): Heat involved in changing phases (no change of T)

Then

Q1 = m*Cp ice * (Tf – T1)

Q2 = m*LH ice

Q3 = m*Cp wáter * (Tb – Tf)

Q4 = m*LH vap

Q5 = m*Cp vap* (T2 – Tb)

**Note** that Tf = 0°C; Tb = 100°C, LH ice = 334
kJ/kg; LH water = 2264.76 kJ/kg.

Cp ice = 2.01 J/g°C ; Cp water = 4.184 J/g°C; Cp vapor = 2.030 kJ/kg°C

Then

Q1 = **10***2.09 * (0 – **-10**) =
209

Q2 = **10***334 = 3340

Q3 = **10***4.184 * (100 – 0) = 4184

Q4 = **10***2264.76 = 22647.6

Q5 = **10***1.84* (110– 100) = 184

QT = Q1+Q2+Q3+Q4+Q5 = 184+22647.6+4184+3340 +209

Qt = 30564.6 J = 30.56 kJ

A) How much heat (in kJ) is required to warm 13.0 g of ice,
initially at -14.0 ∘C, to steam at 114.0 ∘C? The heat capacity of
ice is 2.09 J/g⋅∘C and that of steam is 2.01 J/g⋅∘C
B) How much heat is evolved in
converting 1.00 mol of steam at 130.0 ∘C to ice at -50.0 ∘C? The
heat capacity of steam is 2.01 J/(g⋅∘C) and of ice is 2.09
J/(g⋅∘C).

How much heat (in kJ) is required to warm 12.0 g of ice,
initially at -12.0 ∘C, to steam at 112.0 ∘C? The heat capacity of
ice is 2.09 J/g⋅∘C and that of steam is 2.01 J/g⋅∘C. kJ

How much heat (in kJ) is required to warm 13.0 g of ice,
initially at -10.0 ∘C, to steam at 109.0 ∘C? The heat capacity of
ice is 2.09 J/g⋅∘C and that of steam is 2.01 J/g⋅∘C.

How much heat (in kJ) is required to warm 12.0 g of ice,
initially at -10.0 ∘C, to steam at 111.0 ∘C? The heat capacity of
ice is 2.09 J/g⋅∘C and that of steam is 2.01 J/g⋅∘C.

How much heat (in kJ) is required to warm 13.0 g of ice,
initially at -10.0 ∘C, to steam at 113.0 ∘C? The heat capacity of
ice is 2.09 J/g⋅∘C and that of steam is 2.01 J/g⋅∘C.

12.67
How much heat (in kJ) is required to warm 10.0 g of ice,
initially at -13.0 ∘C, to steam at 112.0 ∘C? The heat capacity of
ice is 2.09 J/g⋅∘C and that of steam is 2.01 J/g⋅∘C.

How much heat (in KJ) is required to warm 13.0 g of ice,
initially at -10.0 *C, to steam at 113.0 degress C? The heat
capacity of ice is 2.09 J/g degress C and that of steam is 2.01 J/g
* C. Show work.

How much heat in kilojoules is required to warm 10.0 g of ice,
initially at -10.0 ∘C, to steam at 125 ∘C. The heat capacity of ice
is 2.09 J/g∘C and that of steam is 1.84 J/g∘C.

5. How much heat (in kJ) is required to warm 10.0 g of ice,
initially at -10.0

Please show each step. Thank you.
How much heat (in kJ) is evolved in converting 1.00 mole of
steam at 145.0 °C to ice at -50.0 °C? The heat capacity of ice is
2.09 J/g°C and that of steam is 2.09 J/g°C
Heat of fusion for water • Hfus = 6.02 kJ/mol
Heat of vaporization for water • Hvap = 40.7 kJ/mol

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