Balance the following redox reaction under acidic conditionsv H2O2 (aq) + NH+(aq)........NO3- (aq)
H2O2 (aq) + NH+(aq)........NO3- (aq)
split in half cells
H2O2 --> H2O
NH+ --> NO3-
balance O
H2O2 --> 2H2O
3H2O + NH+ --> NO3-
Balance H+
2H+ + H2O2 --> 2H2O
3H2O + NH+ --> NO3- + 7H+
balance charges
2e- + 2H+ + H2O2 --> 2H2O
3H2O + NH+ --> NO3- + 7H+ + 7e-
balance e-
14e- + 14H+ + 7H2O2 --> 14H2O
6H2O + 2NH+ --> 2NO3- + 14H+ + 14e-
add all
6H2O + 2NH+ + 14e- + 14H+ + 7H2O2 --> 2NO3- + 14H+ + 14e- + 14H2O
cancel common terms
2NH+ + 7H2O2 --> 2NO3- + 8H2O
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