Employing CFSE concept, explain whether MnCo2O4 is crystallized in a normal spinel or inverse spinel structure
Spinel structure of oxides have the general formula, AB2X4
where, 'A' is divalent ion, 'B' is trivalent ion.
A and B are transition metals,
'A' must have d0 or d5 or d10 configuration
and
'B' must have d1 or d2 or d3 or d4 or d6 or d7 or d8 or d9 configuration .
In the given example,
Mn has +2 oxidation state, and its configuration is (z=25) 3d5 4s0
Co has +3 oxidation state and its configuration is (Z=27) 3d6 4s0
So, the given oxide is suits for the characteristic of spinel structure.
So, MnCoO4 has spinel structure.
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