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The concentrations of Fe2+ and o-phen used in an experiment were 0.00136 M and 0.00407 M,...

The concentrations of Fe2+ and o-phen used in an experiment were 0.00136 M and 0.00407 M, respectively. If a student found a stoichimetric volume ratio of 2.0 mL o-phen to 1.0 mL Fe2+, what is the stoichiometric mole ratio of o-phen to Fe2+? Give your answer to two significant figures.

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Answer #1

        Fe+2 + 3o-Phen --------> Fe(Phen)32+

    no of moles of Fe+2    = molarity * volume in L

                                       = 0.00136*0.002 = 0.00000272 moles

no of moles of O-Phen     = 0.000407*0.001 = 0.000000407moles

    Ratio of Phen to Fe2+   = 3:1

                = 3*0.000000407/0.00000272

                = 0.45

            

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