What are the 95% confidence limits for a control mean of 140 mg/dL and a standard deviation (s) of 2.5 mg/dL?
The formula for calculating 95% confidence limits is shown below.
95% confidence limits = mean ± {t * (s/(n)1/2)}
Where 'n' is the sample size.
In general, the t-value for 95% confidence interval for large sample size = 1.96
For simple example, consider n = 36
Then 95% confidence limits = 140 ± {1.96 * (2.5/(36)1/2)}
i.e. 95% confidence limits = 140 ± 0.81667
i.e. 95% confidence limits = [139.18333, 140.81667]
Note: The values change according to the sample size.
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