Question

How many moles are present in 19.3 g of N2 and 19.3 g of F2?

Answer 1

1)

Molar mass of N2 = 28.02 g/mol

mass of N2 = 19.3 g

we have below equation to be used:

number of mol of N2,

n = mass of N2/molar mass of N2

=(19.3 g)/(28.02 g/mol)

= 0.689 mol

Answer: 0.689 mol

2)

Molar mass of F2 = 38 g/mol

mass of F2 = 19.3 g

we have below equation to be used:

number of mol of F2,

n = mass of F2/molar mass of F2

=(19.3 g)/(38 g/mol)

= 0.508 mol

Answer: 0.508 mol