Question

A)Rank the following acids in order of decreasing acidity given their Ka values.       -...

A)Rank the following acids in order of decreasing acidity given their Ka values.
      -       1.       2.       3.       4.      

H2CO3 Ka = 4.3 x 10−7


      -       1.       2.       3.       4.      

CH3COOH  Ka = 1.8 x 10−5


      -       1.       2.       3.       4.      

HCN   Ka = 4.9 x 10−10


      -       1.       2.       3.       4.      

HNO2 Ka = 4.5 x 10−4

B) What is the Ka of acid HA when the initial concentration of HA is 0.23M and the pH is 3.83?

Express your answer in scientific notation and be mindful of significant figures.

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Answer #1

A

H2CO3 Ka = 4.3 x 10−7 = 4300 x 10−10      (3)

CH3COOH Ka = 1.8 x 10−5 = 1,80,000 x 10−10   (2)

HCN Ka = 4.9 x 10−10 = 4.9 x 10−10   (4)

HNO2 Ka = 4.5 x 10−4   =45,00,000 x 10−10 (1)

HNO2 >CH3COOH > H2CO3 > HCN

B

HA   H+ + B-

pH = 3.83

-log [H+] = 3.83

[H+] = 10-3.83 = 1.48 x 10-4

So,  [B-] = 1.48 x 10-4

[HA] = 0.23 = 2.3  x 10-1

Ka = (1.48 x 10-4 x 1.48 x 10-4) / 2.3  x 10-1

= 9.5 x 10-8

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