Question

3. The pressure inside an unopened can of soda is 2.5 atm (you may assume all of this pressure is from CO2). If the concentration of CO2 under these conditions is 0.080 M, find the Henry’s law constant (in M/atm), and use this to calculate how many grams of CO2 will escape from 355 mL of soda (a 12-oz can) when it is opened to the atmosphere, where the concentration of CO2 is 41 ppm.

Answer 1

Hence, the henry's constant KH=0.080/2.5= 0.032 M/atm

The amount of carbon dioxide escaping out = 0.01455 g .