Question

5.0kg/s cyclohexane is pumped from a height of 2.5m to a height of 15m. Before the pump inlet, the cyclohexane is motionless inside of a holding tank. The diameter of the pipe at the exit point is 2.5 cm. The density of cyclohexane is 779 kg/m3 . Calculate the pump power required in watts and hp. Assume negligible friction. Hint: you will have to include the effect of the outlet velocity

Answer #1

5.0 Kg/s = 18 m^{3}/h

height = (15 m - 2.5 m) = 12.5 m

P_{h(kW)} = q ρ g h / (3.6
10^{6})^{ }

where

P_{h(kW)} = hydraulic power (kW)

q = flow capacity (m^{3}/h)

ρ = density of fluid (kg/m^{3})

g = gravity (9.81 m/s^{2})

h = differential head (m)

The hydraulic Horse Power can be calculated as:

P_{h(hp)} = P_{h(kW)} / 0.746

where

P_{h(hp)} = hydraulic horsepower (hp)

P_{h(KW)} = [18 m^{3}/h x 779 kg/m^{3} x
9.81 m/s^{2} x 12.5 m] / (3.6 x10^{6})

P_{h(KW)} = 0.4776 KW = 477.6 W

P_{h(hp)} = P_{h(kW)} / 0.746 = (0.4776 KW /
0.746) = 0.64 hp

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