Question

# 5.0kg/s cyclohexane is pumped from a height of 2.5m to a height of 15m. Before the...

5.0kg/s cyclohexane is pumped from a height of 2.5m to a height of 15m. Before the pump inlet, the cyclohexane is motionless inside of a holding tank. The diameter of the pipe at the exit point is 2.5 cm. The density of cyclohexane is 779 kg/m3 . Calculate the pump power required in watts and hp. Assume negligible friction. Hint: you will have to include the effect of the outlet velocity ​​

5.0 Kg/s = 18 m3/h

height = (15 m - 2.5 m) = 12.5 m

Ph(kW) = q ρ g h / (3.6 106)

where

Ph(kW) = hydraulic power (kW)

q = flow capacity (m3/h)

ρ = density of fluid (kg/m3)

g = gravity (9.81 m/s2)

The hydraulic Horse Power can be calculated as:

Ph(hp) = Ph(kW) / 0.746

where

Ph(hp) = hydraulic horsepower (hp)

Ph(KW) = [18 m3/h x 779 kg/m3 x 9.81 m/s2 x 12.5 m] / (3.6 x106)

Ph(KW) = 0.4776 KW = 477.6 W

Ph(hp) = Ph(kW) / 0.746 = (0.4776 KW / 0.746) = 0.64 hp

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