Question

When Determining the Solubility of an Unknown Salt at Various Temperatures lab, what procedure change for this experiment would be necessary if the solubility of the salt were initially determined at 10 degrees Celcius instead of 80 degrees Celcius, followed by solubility determinations at 20,35, 50,65, and 85 Degrees Celcius.

Answer 1

If we start at high Temperature, then the solubility is at its MAX (typically, actually it depends on type of salt, but in general, the solubility increases as T increases)

Therefore, it is much recommendable to start at higher Temperature, so the solid that preciptiates can be measured as Temperature drops, therefore, solubility cna be calculated as:

Solubility = Mass dissolved / Total volume = (Initial Mass - Precipitated Mass) / Total volume

now...

If we start backwards; we will have to perform this each time:

- Start with any amount of salt, then keep adding until no more is solulbe and only preciptiates/solids are forming in the bottom

Calculate How much is left --> mass in solution --> calcualte solubility

then, 2nd test:

Icnrease Temperature, therefore solubility increases, we must repeat:

- Start with any amount of salt, then keep adding until no more is solulbe and only preciptiates/solids are forming in the bottom

Calculate How much is left --> mass in solution --> calcualte solubility

Keep doing this until we get all Tempearture intervals