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#34. A buffer solution contains 0.71 mol of hydrogen peroxide (HOOH) and 0.41 mol of sodium...

#34. A buffer solution contains 0.71 mol of hydrogen peroxide (HOOH) and 0.41 mol of sodium hydrogen peroxide (NaOOH) in 7.60 L.
The Ka of hydrogen peroxide (HOOH) is Ka = 2.4e-12.

(a) What is the pH of this buffer?

pH = ___


(b) What is the pH of the buffer after the addition of 0.36 mol of NaOH? (assume no volume change)

pH = ___


(c) What is the pH of the original buffer after the addition of 0.28 mol of HI? (assume no volume change)

pH = ___

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Answer #1

34

a) pH of buffer = pka + log(salt/acid)

       pka = -logka

            = -log(2.4*10^-12)

            = 11.62

[salt] = [NaOOH] = 0.41 mole

[acid] = [H2O2] = 0.71 mole

pH = 11.62 + log(0.41/0.71)

    = 11.38

b) pH of buffer = pka + log(salt+NaOH/acid-NaOH)

   pH = 11.62 + log((0.41+0.36)/(0.71-0.36))

       = 11.96

c) pH of buffer = pka + log(salt-HCl/acid+HCl)

   pH = 11.62 + log((0.41-0.36)/(0.71+0.36))

       = 10.29

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