Question

Proton mass mp = 1.00727647 u

Neutron mass mn = 1.00866501 u

231Th mass = 231.036299 u

Avogadro

Answer #1

Question 1. 1. Alpha decay of uranium-235 to thorium

^{235}_{92}U ^{231}_{90}Th
+ ^{4}_{2}He

2. Q = (Mp -Md-M?)amu. Mp = mass of parent nuclei, Md = mass of daugther nuclei, M? = mass of alpha particle

Q = M^{235}_{92}U -
(M^{231}_{90}Th - M ^{4}_{2}He)

= M^{235}_{92}U - M^{231}_{90}Th
+ M ^{4}_{2}He

= M ^{4}_{2}He + M
^{4}_{2}He

= 4.002603 u + 4.002603 u

**Q = 8.005206 u**

3. mass of uranium-235

Q = M^{235}_{92}U -
(M^{231}_{90}Th - M ^{4}_{2}He)

substitute all the values to calculate mass of uranium

**8.005206 u =** M^{235}_{92}U -
( 231.036299 u - 4.002603 u)

**8.005206 u + (** **231.036299 u - 4.002603
u) = M ^{235}_{92}U**

**235.038902 u =
M ^{235}_{92}U**

4. binding energy of the nucleus.

235 - 92 = 143 neutrons

Total mass of baryons is (92 x 1.00727647) + (143 x 1.00866501) = 236.9085188 u

Mass defect = 236.9085188 - 235.038902 = 1.8645889 u =
3.096222181 x 10^{-27} kg

**E=mc^2 = 3.096222181 x
10 ^{-27} kg
x (3.00x10^8)^2 = 2.86351 x 10^-10 J
= 1.74 GeV**

You know that: mass of proton (mp) = 1.007276 amu, mass of
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Proton mass = 1.0078 u
Neutron mass = 1.0087 u
Mass of 226/88 Ra = 226.0244 u
a) Determine the mass defect for this isotope.
b) Determine the binding energy for nucleon for this isotope.
c) Radium-88 undergoes alpha decay via the following equation:
226/88Ra = 222/86Rn + 4/2He + Q
If the mass of the radon-86 isotope is 222.0165 u and the mass of
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