Question

Calculate the Coulomb attraction between the atoms of the following salts:

a) Cesium Chloride (CsCl) b) Rutile (TiO2)

*This is all that was given*

Answer 1

Coulomb attraction between the atoms is calculated with the help of formula, F = -A/r² where A= A₀(Z₁e)(Z₂e) and A₀ is proportionality constant (9x10⁹ V/C) , Z is valence of the charged ion (+1 for Cs and -1 for Cl) , e is single electron charge (1.602x10^-19 C) and r = r_Cs⁺¹ + r_Cl^-1 = (0.167 + 0.181)nm = 0.348x10^-9 m

So, we can substitute the values in the above formula:

F= - (9x10⁹)(+1)(1.602x10^-19)(-1)(1.602x10^-19) / (0.348x10^-9)² = 190.66x10^-11 N

Similarly we can calculate for rutile (TiO₂) here Ti is in +4 oxidation state and O in -2.

r = r_Ti⁺⁴+ r_O^2- = 0.060 + 0.140 = 0.200nm = 0.200x10^-9 m

F = -(9x10⁹)(+4)(1.602x10^-19)(-2)(1.602x10^-19) / (0.200x10^-9)² = 4619.52x10^-11 N