Question

45 mEq/L EACH OF K+ and C-

How many moles of K + are in 1.5 L of the solution?

Answer #1

45mEq/L of K^+ is same 45m mole/L

45 m mole/L = 0.045mole/L

no of moles of K^+ = molarity * volume in L

= 0.045mole/L * 1.5 L

= 0.0675 moles of K^+

A
solution to replace potassium loss contains 43 mEq/L each of K+and
Cl-
1- how many moles of K+ are in 1.9 L of the solution?
_________\_= mole K+
2- how many moles of Cl- are in 1.9 L of the solution
__________=molCl-
Express your answer using two sig figs

A
solution to replace potassium loss contains 43 mEq/L each of K+ and
Cl-
1- how many moles of K+ are in 1.9 L of the solution?
Express your answer using two dig figs
--------= molK+
2- how many moles of Cl- are in 1.9 L of the solution
Express your answer using two sig figs
---------= molCl-

A Pedialyte solution contains Na+ 41 mEq/L , K+ 24 mEq/L , Cl−
34 mEq/L , citrate3− 31 mEq/L , and glucose (C6H12O6) 25 g/L .
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What is the total positive charge of the electrolytes?
Part B
What is the total negative charge of the electrolytes?
Part C
What is the osmolarity (Osm ) of the solution?

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significant figures. mol SubmitMy AnswersGive Up Part B 0.408 L of
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Express your answer using two significant figures.
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Express your answer using two significant figures.
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Express your answer using three significant figures.

part a: How many moles of gas does a 1.00 L container is filled
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part b: How many moles of N2 gas are there in a 1.0 L
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part c: How many moles of O2 gas are there in a 1.0 L
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__________mol of aluminum
______ x 10^ _______ aluminum ions
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