Question

(b) Based on your knowledge of the periodic trend in first ionization energy, place the following in order of INCREASING first ionization energy such that 1 is the element with the lowest predicted first ionization energy and 5 is the element with the highest predicted first ionization energy.


1 2 3 4 5  Zn
1 2 3 4 5  Sr
1 2 3 4 5  N
1 2 3 4 5  Ca
1 2 3 4 5  Ti

Incorrect.

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(c) Based on your knowledge of the periodic trend in atomic radius, place the following in order of INCREASING atomic radius such that 1 is the element with the smallest predicted atomic radius and 5 is the element with the largest predicted atomic radius.


1 2 3 4 5  Tc
1 2 3 4 5  As
1 2 3 4 5  Rh
1 2 3 4 5  Zr
1 2 3 4 5  Mo

Answer 1

Ionization energy : The enrgy required for the removal of electron form its valecy shell in its free state (i.e., free from all interactions except from nucleus)

Atomic configurations

Zn - [Ar] 3d10 4s2 --------4

Sr - [Kr] 5s2 -------------1

N - 1s2 2s2 2p3 -----------5

Ca - [Ar] 4s2 -------------2

Ti - [Ar] 3d2 4s2 ---------3

order of atomic sizes: Sr > Ca > Ti > Zn > N

Ionization energy: Sr < Ca < Ti < Zn < N

Tc - [Kr] 4d5 5s2 ---------3

As - [Ar] 3d10 4s2 4p3 ----1

Rh - [Kr] 4d8 5s1 ---------2

Zr - [Kr] 4d2 5s2 ---------5

Mo - [Kr] 4d5 5s1 ---------4

If the number of electron increasing in the same shell then the ineraction from nucleaus to outer electron increses so the atomic radii increases.