Question

How many grams of sodium contain the same number of atoms as 12.4 g of potassium? Using correct significant figures.

Answer #1

Molar mass of Na = 22.99 g/mol

Molar mass of *K* = 39.10 g/mol

First calculate number of K atoms in 12.4 g of potassium sample as:

Number of K atom in 39.10 g of potassium is 6.022 × 10
^{23} (**Avogadro's number**)

Hence, number of atom of K in 12.4 g of potassium = 6.022 × 10
^{23} x 12.4 / 39.10

= 74.67 x 10^{23} / 39.10

= 1.909 x 10^{23} atomsof K

Now,

Since, 6.022 × 10 ^{23} atoms of Na are present in 22.99
g (1mole) of sample of sodium

then mass of sodium which contain 1.909 x 10^{23}
atomsof Na = 1.909 x 10^{23} x 22.99 / 6.022 ×
10 ^{23}

= 43.887 x 1023 / 6.022 × 10 ^{23}

= **7.28 g of sodium sample.**

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