Question

A) If you dialyze 40 ml of protein in 8 M urea against 2 liters of...

A) If you dialyze 40 ml of protein in 8 M urea against 2 liters of 50 mM NaCl solution, what will be the urea molar concentration in the dialysis bag at equilbrium?

B) You need to reduce the urea concentration to less than 1 mM. How many rounds of dialysis will you need to make if you use 2 liters of 50 mM NaCl each time and you let each dialysis proceed to equilibrium?

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Answer #1

a) 8M urea has 8 x 60 = 480 g of urea.

During dialysis water and small molecules flow freely through a dialysis membrane. This 8 M urea will be distrubuted through 2 Litres of water and its concentration will reduce to 4M as 4 M means 4 moles/litre.

b) Every round of dialysis against 2 litres of water will reduce the urea concentration by half. Thus to reduce 8 M urea to 1 mM you will have to do the dialysis n number of times in the equation 8/2n = 1 x 10-3. If you solve for this you will get n = 13.

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