Question

Calcium oxide reacts with water in a combination reaction to produce calcium hydroxide: BaO(s)+H2O(l)-->Ba(OH)2(s) In a particular experiment, a 1.50-g sample of BaO is reacted with excess water and 1.29 g of Ba(OH)2 is recovered. Calculate the theoretical yield and the percent yield of Ba(OH)2 in this experiment.

Answer 1

To calculate the percentage yield of any reaction, we need a balanced equation.

BaO+H2O=Ba(OH)2

From this balanced equation we can see that 1 mole of BaO gives 1 mol of barium hydroxide. As water is in excess, we will not consider it.

Now,

153.33 g of BaO (1 mol) gives= 171.34 g of barium hydroxide(1 mol)

So , 1.5g of BaO will give = 171.34/153.33 × 1.5g

=1.676g

Now, our experimental yield is = 1.29g

Percentage yield = experimental yield/ theoretical yield × 100

= 1.29÷1.676 × 100

=76.96%