Question

measuring the density of antifreeze: temperature of antifreeze: 19.8 C mass of flask + antifreeze: 47.6849, 55.2439, 65.2403 (grams) mass of empty flask: 36.2795 (grams) mass of antifreeze: 10.2957, 19.1505, 27.7812 (g) a. calculate density of antifreeze b. mean (average) density c. average deviation from the mean

volume is 10 mL

Answer 1

a) 1. Mass of anti freeze = M₁= Mass of (Flask+Antifreeze) - Mass of empty flask = 47.6849-36.2795= 11.4054 g

Volume = 10ml

So Density D₁= mass/volume = 11.4054/10 = 1.140 g/ml

2. Mass of antifreeze = 55.2439 - 36.2795 = 18.9644 g

Density D₂ = 18.9644/10 = 1.896 g/ml

3. Mass of anti freeze = 65.2403 - 36.2795 = 28.9608 g

Density D₃ = 28.9608/10 = 2.896 g/ml

b) Mean Density = Sum of densities/ No. of observations

= (1.140+1.896+2.896)/3

= 5.932/3 = 1.977 g/ml

c) Average deviation = Sum of absolute value of individual deviation / No. of observations

= ( |1.977-1.140| + |1.977-1.896| + |1.977-2.896|) / 3

= (0.837+0.081+0.919) / 3

= 1.837/3 = 1.224