Question

The pKa of Ampicillin is 2.5. What is the between the conjugate base and acid of...

The pKa of Ampicillin is 2.5. What is the between the conjugate base and acid of ampicillin when the stomach acid has a PH of 1.4? What is the ratio when in the small intestine (the small intestine has a PH of 6?). From your answers, explain if more ampicillin is absorbed into the bloodsteam through the stomach or small intestine?

Homework Answers

Answer #1

This should be claculated with buffer equation, since it is easier to calculate:

pH = pKa + log(conjugate/acid)

the ratio is = conjugate/acid

so

pH = pKa + log(ratio)

pKa = 2.5 so

pH = 2.5 + log(ratio)

for the stomach acid, pH = 1.4

substitute and solve

1.4 = 2.5 + log(ratio)

ratio = 10^-(1.4-2.5) = 12.5892

ratio = 12.5892

Q2

for intestine, pH = 6

so

pH = pKa + log(ratio)

6 = 2.5 + log(ratio)

ratio = 10^(6-2.5) = 3162.27

Clearly, this is absorbed in its ionic state, so it must be absorbed in the ph = 6, i.e. small intestine

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