Question

1)

Molecules of I₂ are produced by the reaction of 0.3737 mol of CuCl₂ according to the following equation.

2 CuCl₂ + 4 KI → 2 CuI + 4 KCl + I₂

(a) How many molecules of I₂ are produced?

(b)What mass (in g) of I₂ is produced?

2)

What mass (in g) of silver oxide, Ag₂O, is required to produce 26.7 g of silver sulfadiazine, AgC₁₀H₉N₄SO₂, from the reaction of silver oxide and sulfadiazine?

2 C₁₀H₁₀N₄SO₂ + Ag₂O → 2 AgC₁₀H₉N₄SO₂ + H₂O

Thank you in advance for any help :)

Answer 1

1)

2 CuCl₂ + 4 KI → 2 CuI + 4 KCl + I₂

_​​2 mol of CuCl2 produces 1 mol of I2

0.3737 mol of CuCl₂ will produce I2 = (0.3737 x 1)÷2

= 0.18685 mol of I2

a) 1 mol = 6.022 x 10 ²³ molecule

0.18685 mol of I2 = 1.162 x 10 ²³ molecules

b) mass of I2 produced = 0.18685 x 253.8 g

= 47.42 g

2) 2 C₁₀H₁₀N₄SO₂ + Ag₂O → 2 AgC₁₀H₉N₄SO₂ + H₂O

Molar mass of silver sulfadiazine is 357.13 g/ mol

2 mol of silver sulfadiazine requires 1 mol of Ag2O

2 X 357.13 of silver sulfadiazine requires 231.735 g Ag2O

26 g of silver sulfadiazine requires Ag2O = (26 x 231.735. ) ÷ 714.26

= 8.435 g Ag2O