Question

A sample of 1.699g of an unknown compound container silver is dissolved in water and treated with an ecesss of sodium chloride in acidic condition. F the mass of the silver chloride precipitate formed is 1.434g, what is the percent by mass of silver in our original unknown compound

Answer 1

Amount of AgCl formed: 1.434 g

Amount of Ag in 1.434 g AgCl = (Molar mass of Ag/Molar mass of AgCl) x 1.434 g

                                                     = (107.87/143.32) x 1.434 = 1.079

Amount of crude = 1.699 g

% of silver = (Actual amount/Crude)x100 = (1.079/1.699)x 100 = 63.51%