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Calculate the following quantity: molarity of a solution
prepared by diluting 45.77 mL of 0.0371 M
ammonium sulfate to 450.00 mL.
Answer:
Step 1: Explanation
We can solve for the concentration or volume of the concentrated or dilute solution using the equation:
M1V1 = M2V2
where, M1 = concentration in molarity (moles/Liters) of the concentrated solution,
V1 = the volume of the concentrated solution,
M2 = the concentration in molarity of the dilute solution
and V2 = the volume of the dilute solution.
Step 2: Solution
Given,
M1 = 0.0371 M
V1 = 45.77 mL
M2 = we need to calculate
and V2 = 450 mL
So, on substituting the value
M1V1 = M2V2
=> M2 = ( M1V1 ) / V2 = ( 0.0371 M × 45.77 mL ) / 450 mL = 0.0037735 M
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