Question

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Calculate the following quantity: molarity of a solution prepared by diluting 45.77 mL of 0.0371 M ammonium sulfate to 450.00 mL.

Answer 1

Answer:

Step 1: Explanation

We can solve for the concentration or volume of the concentrated or dilute solution using the equation:

M₁V₁ = M₂V₂

where, M₁ = concentration in molarity (moles/Liters) of the concentrated solution,

V₁ =  the volume of the concentrated solution,

M₂ = the concentration in molarity of the dilute solution

and V₂ = the volume of the dilute solution.

Step 2: Solution

Given,

M₁ = 0.0371 M

V₁ = 45.77 mL

M₂ = we need to calculate

and V₂ = 450 mL

So, on substituting the value

M₁V₁ = M₂V₂

=> M₂ = ( M₁V₁ ) / V₂ = ( 0.0371 M × 45.77 mL ) / 450 mL = 0.0037735 M