Question

A 1.000 kg block of ice at 0 °C is dropped into 1.354 kg of water...

A 1.000 kg block of ice at 0 °C is dropped into 1.354 kg of water that is 45 °C. What mass of ice melts?

Specific heat of ice = 2.092 J/(g*K) Water = 4.184 J/(g*K)   Steam = 1.841 J/(g*K) Enthalpy of fusion = 6.008 kJ/mol Enthalpy of vaporization = 40.67 kJ/mol

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
How much heat is released when 105 g of steam at 100.0°C is cooled to ice...
How much heat is released when 105 g of steam at 100.0°C is cooled to ice at -15.0°C? The enthalpy of vaporization of water is 40.67 kJ/mol, the enthalpy of fusion for water is 6.01 kJ/mol, the molar heat capacity of liquid water is 75.4 J/(mol • °C), and the molar heat capacity of ice is 36.4 J/(mol • °C).
To change 25 kg of ice -10°C to steam 100°C, how much heat is required? The...
To change 25 kg of ice -10°C to steam 100°C, how much heat is required? The specific heat of water is 4.184 kJ/kg. K. The latent heat of fusion for water at 0°C is approximately 334 kJ/kg (or 80 cal/g), and the latent heat of vaporization at 100°C is about 2,230 kJ/kg (533 cal/g).
What mass of steam at 100∘C must be added to 1.10 kg of ice at 0∘C...
What mass of steam at 100∘C must be added to 1.10 kg of ice at 0∘C to yield liquid water at 19 ∘C? The heat of fusion for water is 333 kJ/kg , the specific heat is 4186 J/kg⋅C∘ , the heat of vaporization is 2260 kJ/kg .
What mass of steam at 100∘C must be added to 1.00 kg of ice at 0∘C...
What mass of steam at 100∘C must be added to 1.00 kg of ice at 0∘C to yield liquid water at 18 ∘C? The heat of fusion for water is 333 kJ/kg , the specific heat is 4186 J/kg⋅C∘J/kg⋅C∘ , the heat of vaporization is 2260 kJ//kg . Express your answer to two significant figures and include the appropriate units m=
A 500.0-g sample of an element at 153°C is dropped into an ice-water mixture; 109.5-g of...
A 500.0-g sample of an element at 153°C is dropped into an ice-water mixture; 109.5-g of ice melts and an ice-water mixture remains. Calculate the specific heat of the element from the following data: Specific heat capacity of ice: 2.03 J/g-°C Specific heat capacity of water: 4.18 J/g-°C H2O (s) → H2O (l), ΔHfusion: 6.02 kJ/mol (at 0°C) a) If the molar heat capacity of the metal is 26.31 J/mol-°C, what is the molar mass of the metal, and what...
The enthalpy change for converting 10.0 g of ice at -25.0 degrees C to water at...
The enthalpy change for converting 10.0 g of ice at -25.0 degrees C to water at 80.0 degrees C is _______kJ.  The specific heats of ice, water, and steam are 2.09 J/g-K, 4.18 J/g-K, and 1.84 J/g-K, respectively.  For H2O, Delta Hfus=6.01 kJ/mol, and Delta Hvap=40.67 Kj/mol Please explain steps used as well. Thank you.
A 485.4-g sample of an element at 192°C is dropped into an ice–water mixture; 117.0 g...
A 485.4-g sample of an element at 192°C is dropped into an ice–water mixture; 117.0 g of ice melts and an ice–water mixture remains. Calculate the specific heat of the element. ΔHfusion = 6.02 kJ/mol (for liquid water at 0°C). Specific heat =______ J/g∙°C
Two 20.0-g ice cubes at –20.0 °C are placed into 285 g of water at 25.0...
Two 20.0-g ice cubes at –20.0 °C are placed into 285 g of water at 25.0 °C. Assuming no energy is transferred to or from the surroundings, calculate the final temperature, Tf, of the water after all the ice melts. heat capacity of H2O(s) is 37.7 J/mol*K heat capacity of H2O(l) is 75.3 J/mol*K enthalpy of fusion of H20 is 6.01 kJ/mol
Two 20.0-g ice cubes at –13.0 °C are placed into 275 g of water at 25.0...
Two 20.0-g ice cubes at –13.0 °C are placed into 275 g of water at 25.0 °C. Assuming no energy is transferred to or from the surroundings, calculate the final temperature of the water after all the ice melts. heat capacity of H2O(s) 37.7 J/(mol*k) heat capacity of H2O(l) 75.3 J/(mol*k) enthalpy of fusion of H2O 6.01 kJ/mol
Two 20.0-g ice cubes at –18.0 °C are placed into 245 g of water at 25.0...
Two 20.0-g ice cubes at –18.0 °C are placed into 245 g of water at 25.0 °C. Assuming no energy is transferred to or from the surroundings, calculate the final temperature of the water after all the ice melts. Please show work. Heat capacity of H20(s): 37.7 J/(mol x K) Heat capacity of H20(l): 75.3 J/(mol x K) Enthalpy of fusion of H20: 6.01 kJ/mol
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT