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Calculate ΔG (in kJ) at 65 oC for the reaction: N2O(0.0027 atm) + H2(0.43 atm) ↔...

Calculate ΔG (in kJ) at 65 oC for the reaction: N2O(0.0027 atm) + H2(0.43 atm) ↔ N2(890.2 atm) +H2O(l)

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Answer #1

Reaction quotiet Qp = pN2 / ( pN2O x pH2)           liquids liek H2O not included in eq

Qp = ( 890.2 atm) / ( 0.0027 atm x 0.43 atm)

     = 766753

dGo of reaction = dGo products - dGo reactants

    = dGo N2 + dGo H2O (l) - dGo N2O - dGo H2

    =     0 - 237.14 KJ/mol - 103.8 KJ/mol - 0

           = -340.94 KJ/mol = -340940 J/mol

dG = dGo + RT ln Qp   is formula   where T = 65C = 65+273 = 338 K

dG = -340940 J/mol + ( 8.314 J/molK x 338 K) ln ( 766753)

= -302862 J/mol = -302.86 KJ/mol

= -303 KJ/mol

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