Question

Calculate the molarity (M) of 159.2 g of H2SO4 in 1.145 L of solution.

Answer 1

Molar mass of H2SO4 = 2*MM(H) + 1*MM(S) + 4*MM(O)

= 2*1.008 + 1*32.07 + 4*16.0

= 98.086 g/mol

mass(H2SO4)= 159.2 g

we have below equation to be used:

number of mol of H2SO4,

n = mass of H2SO4/molar mass of H2SO4

=(159.2 g)/(98.086 g/mol)

= 1.623 mol

volume , V = 1.145 L

we have below equation to be used:

Molarity,

M = number of mol / volume in L

= 1.623/1.145

= 1.42 M

Answer: 1.42 M