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Lead(II) nitrate and ammonium iodide react to form lead(II) iodide and ammonium nitrate according to the...

Lead(II) nitrate and ammonium iodide react to form lead(II) iodide and ammonium nitrate according to the reaction Pb(NO3)2(aq)+2NH4I(aq)⟶PbI2(s)+2NH4NO3(aq) What volume of a 0.290 M NH4I solution is required to react with 501 mL of a 0.620 M Pb(NO3)2 solution? How many moles of PbI2 are formed from this reaction?

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