Question

Calculate the wavelength of the photon emitted when the hydrogen atom undergoes a transition from n=8 to n=4. (R=1.096776x10^7m-1)

Please explain hwo you got the answer

Answer 1

From Rydburg's Equation , 1/ λ = R[(1/n_i²) – (1/n_f²)]
   Where R = Rydburg's constant = 10.96 x10⁶ m^-1
               λ = wavelength = ?
               n_i = 4
               n_f = 8
Plug the values we get  1/ λ = 10.96 x10⁶ [(1/4²) – (1/8²)]

= 513.75x10³

  λ = 1.946x10^-6 m

Therefore the wavelength of the photon emitted is  1.946x10^-6 m