Question

The activation energy, Ea for a particular reaction is 13.6 kj/mol. If the rate constant at 754 degrees celsius is 24.5/min at egat temperature in celsius will the rate constant be 12.7/min? r= 8.314j/mol • K

Answer #1

what is the activation energy(Ea) of a first order reaction is
the reaction rate constant(k) increases from 0.0300 min to 0.500
min as the temperature increases from 20.0 C to 45.0 C?

A)The activation energy of a certain reaction is 33.8 kJ/mol .
At 30 ∘C , the rate constant is 0.0170s−1. At what
temperature in degrees Celsius would this reaction go twice as
fast?
B)Given that the initial rate constant is 0.0170s−1 at an
initial temperature of 30 ∘C , what would the rate constant be at a
temperature of 200. ∘C for the same reaction described in Part
A?

The activation energy of a certain reaction is 35.1 kJ/mol . At
25 ∘C , the rate constant is 0.0160s−1. At what temperature in
degrees Celsius would this reaction go twice as fast?
Given that the initial rate constant is 0.0160s−1 at an initial
temperature of 25 ∘C , what would the rate constant be
at a temperature of 200. ∘C for the same reaction
described in Part A?

The activation energy of a particular reaction is 245 kJ/mol.
How many degrees above room temperature (25°C) would the reaction
need to be heated in order to see a 10 fold increase in the rate
constant?

1.a)The activation energy of a certain reaction is 46.3 kJ/mol .
At 30 ∘C , the rate constant is 0.0180s−1. At what temperature in
degrees Celsius would this reaction go twice as fast?
b) Given that the initial rate constant is 0.0180s−1 at an
initial temperature of 30 ∘C , what would the rate constant be at a
temperature of 140 C for the same reaction described in Part A?

Part A: The activation energy of a certain
reaction is 43.5 kJ/mol . At 23 ∘C , the rate constant is
0.0180s−1. At what temperature in degrees Celsius would this
reaction go twice as fast?
Part B: Given that the initial rate constant is
0.0180s−1 at an initial temperature of 23 ∘C , what would the rate
constant be at a temperature of 190. ∘C for the same reaction
described in Part A?

Part A: The activation energy of a certain reaction is 42.3
kJ/mol . At 29 ∘C , the rate constant is 0.0170s−1 . At what
temperature in degrees Celsius would this reaction go twice as
fast?
Part B: Given that the initial rate constant is 0.0170s−1 at an
initial temperature of 29 ∘C , what would the rate constant be at a
temperature of 120. ∘C for the same reaction described in Part
A?

Part A:
The activation energy of a certain reaction is 42.8 kJ/mol . At
28 ∘C , the rate constant is 0.0190s−1. At what temperature in
degrees Celsius would this reaction go twice as fast?
Part B:
Given that the initial rate constant is 0.0190s−1 at an initial
temperature of 28 ∘C , what would the rate constant be
at a temperature of 150 ∘C for the same reaction
described in Part A?

a.)A certain reaction has an activation energy of 25.10 kJ/mol.
At what Kelvin temperature will the reaction proceed 7.00 times
faster than it did at 289 K?
b.A certain reaction has an enthalpy of ΔH = 39 kJ and an
activation energy of Ea = 51 kJ. What is the activation energy of
the reverse reaction?
c.)At a given temperature, the elementary reaction A<=> B in
the forward direction is the first order in A with a rate constant
of...

A. The activation energy of a certain reaction is 42.0 kJ/mol .
At 29 ∘C , the rate constant is 0.0190s-1. At what
temperature in degrees Celsius would this reaction go twice as
fast? Express your answer with the appropriate units.
B. Given that the initial rate
constant is 0.0190s-1 at an initial temperature of 29 C
, what would the rate constant be at a temperature of
120. ∘C for the same reaction described in Part
A?
Express your answer...

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