A water supply contains 0.5 mg/L ammonia (as nitrogen). Estimate the Cl2 dose in mg/L that would be required to reach breakpoint if no other chlorine-demanding substances are present.
Breakpoint - when chloroamines breakdown and converted to N gas which leaves the system.
when we see the reaction between ammonia and Cl2 we see that 3 moles of Cl2 is required to Oxidise 2moles of NH3 to N2 .
that means 213gram (mass of three moles of Cl2) is required for reacting with 34 gram of ammonia (2moles)
now we know one mole of ammonia weighs = 17 gram
i.e nitrogen in 17gram ammonia = 14 gram
therefore nitrogen in 34 gram ammonia= (14/17)*34 = 28gram nitrogen
In the question we are given water supply contain 0.5 milligram of ammonia per litre of water
that means it contains (0.5)(14/17) milligram of nitrogen per litre of water i.e 0.411mg/L
we calculate above that 7.6 gram Cl2 is required per gram of nitrogen
i.e 7.6 mg og Cl2 per mg of nitrogen
therefore Cl2 required for 0.411mg/L of nitrogen = (7.6)*(0.411)= 3.12mg/ltr
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