A student is givrn a stock solution of red dye that has a concentration of 5.682x10^-5 M. The student is asked to make five dilute solutions from this stock solution. Information for the five solutions is providen in the table below. Calculate the concentration of each solution, be sure to show your work very neatly below the table
Solution Name | Volume Of Stock | Final Volume |
Final Concentration (M) |
Solution 1 | 1mL | 200mL | |
Solution 2 |
2mL | 200mL | |
Solution 3 |
3mL | 200mL | |
Solution 4 |
4mL | 200mL | |
Solution 5 |
5mL | 200mL |
Solution Name
Volume Of Stock | Final Volume |
Final Concentration (M) |
|
Solution 1 | 1mL | 200mL | 2.841 x 10^-7 |
Solution 2 |
2mL | 200mL | 5.628 x 10^-7 |
Solution 3 |
3mL | 200mL | 8.523 x 10^-7 |
Solution 4 |
4mL | 200mL | 1.136 x 10^-6 |
Solution 5 |
5mL | 200mL | 1.421 x10^-6 |
explanation:
molarity of stock solution = C1 = 5.682 x 10^-5 M
stock solution volume for 1) = V1 = 1 mL
final volume = V2 = 200 mL
final concentration =C2 = ?
dilution formula : C1 V1 = C2 V2
5.682 x 10^-5 x 1 = C2 x 200
C2 = 2.841 x 10^-7 M
similary solve 2,3,4,5
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