Question

Mixing of s and p orbitals can lead to some strange effects and very unstable structures that
cannot be accurately described using Lewis structures. For each part, name the (n = 2)
homonuclear diatomic (e.g. Li2, N2, Ne2, etc.) that each statement represents.

(c) A molecule with eight electrons in bonding orbitals but has a bond order of zero.

Answer 1

in a molecular orbital theory, filling orbitals with increasing energy levels,so using that if total no of electrons <14

for a homogeneous diatomic molecules order is

1s < ^*1s < 2s < ^* 2s< _2py=_2pz<2px<-------------

    bond order = 1 /2 ( Nb   - Na),     where Nb = bonding no of electrons,   Na =antibonding no of electrons

                   if it is 8 electrons ,bonding =4, antibonding =4

                   bond order = 1/2 ( 4 -4) = 0, it shows that bonding does not exist.

                         thank u