Balance the following chemical equation and determine the number of moles of CO2(g) produced when 4.05 x 1020 molecules of C6H12O6(s) react with excess O2(g) to produce CO2(g) and H2.
C6H12O6(s) + O2(g) → CO2(g) + H2(l)
The balanced equation is
C6H12O6 (s) + 6O2 --> 6CO2 ( g) + 6H2O (l)
Number of Glucose moles = number of molecules / avagadro number
= ( 4.05x10^20 ) / ( 6.023x10^23) = 0.0006724
As per reaction 1 glucose gives 6 CO2
Hence number of moles of CO2 = 6 x glucose moles
= 6 x 0.0006724 = 0.0040345
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