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If 500 mL of 2.00

If 500 mL of 2.00

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Answer #1

in 1 litter of water the new concentration for Barium and fluoride are:

[Ba++] =

[F-] =

when you evaluate the Q acconding to this reaction BaF2 Ba+2 + 2F-

Q = [Ba+2][F-]2  = (1x10-3)x(1x10-3)2 = 1x10-9

Since Q Ksp there is no precipitate.

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The answer is A because when you dissolven K2CO3 in water, this happens:

K2CO3   2 K+ + CO32-

CO32-   + H2O HCO3-  + OH- (it produces OH- So the pH increases)

The rest of the anions NO3- and Cl-  don't react with water then they don't yield OH-. They don't react with water because they came from strong acid (HNO3 and HCl) and they will be then very weak bases.

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