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How much heat (in kJ) is needed when 117.42 g of water warms and boils from...

How much heat (in kJ) is needed when 117.42 g of water warms and boils from 52.64oC to 100oC?

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Answer #1

water convert 52.640C to 1000C

m = 117.42g

c = 4.184J/g-0C

q = mcT

      = 117.42*4.184*(100-52.64)

      = 23267.3J      = 23.2673KJ

water

Hvap = 2.26Kj/g

q2 =mHvap

      = 117.42*2.26   = 265.3692KJ

q   = q1 + q2

        = 23.2673 + 265.3692   = 288.6365KJ >>>>answer

   

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