Question

When 3.036 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 10.26 grams...

When 3.036 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 10.26 grams of CO2 and 2.101 grams of H2O were produced. In a separate experiment, the molar mass of the compound was found to be 26.04 g/mol. Determine the empirical formula and the molecular formula of the hydrocarbon.

Homework Answers

Answer #1

Empirical formula is the least coefficient formula, that is

CxHy

we must find x,y,z via gravimetry.

Typically we do this relating to moles of C,H,O

mol of CO2 = mass of CO2/MW of CO2 = (10.26)/(44) = 0.2331 mol of CO2

1 mol of CO2 = 1 mol of C ---> 0.2331 mol of CO2 = 0.2331 mol of C

mol of H2O = mass of H2O/MW of H2O= (2.101)/(18) = 0.1167 mol of H2O

1 mol of H2O= 2 mol of H ---> 0.1167 mol of H2O= 0.1167*2 = 0.2334 mol of H

ratio

H:C =0.2334 / 0.2331 = 1

CH is the empirical formula

for overall formula

MW empirical = C+H = 12+1 = 13 g/mol

Ratio

MW real / MW empirical = 26/13 = 2x

so

C2H4 ---> molecular formula

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
When 4.748 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 16.05 grams...
When 4.748 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 16.05 grams of CO2 and 3.286grams of H2O were produced. In a separate experiment, the molar mass of the compound was found to be 26.04 g/mol. Determine the empirical formula and the molecular formula of the hydrocarbon. empirical formula = ? molecular formula = ?
When 2.050 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 6.280 grams...
When 2.050 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 6.280 grams of CO2 and 3.000grams of H2O were produced. In a separate experiment, the molar mass of the compound was found to be 86.18 g/mol. Determine the empirical formula and the molecular formula of the hydrocarbon. empirical formula =? molecular formula =?
When 3.793 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 12.34 grams...
When 3.793 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 12.34 grams of CO2 and 3.791grams of H2O were produced. In a separate experiment, the molar mass of the compound was found to be 54.09 g/mol. Determine the empirical formula and the molecular formula of the hydrocarbon.
When 3.795 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 13.03 grams...
When 3.795 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 13.03 grams of CO2 and 2.134 grams of H2O were produced. In a separate experiment, the molar mass of the compound was found to be 128.2 g/mol. Determine the empirical formula and the molecular formula of the hydrocarbon.
In a combustion analysis of a hydrocarbon, 11.0 grams of CO2 and 6.78 grams of H2O...
In a combustion analysis of a hydrocarbon, 11.0 grams of CO2 and 6.78 grams of H2O are produced. What is the empirical formula of the hydrocarbon?
A 5.797 gram sample of an organic compound containing C, H and O is analyzed by...
A 5.797 gram sample of an organic compound containing C, H and O is analyzed by combustion analysis and 9.656 grams of CO2 and 3.163 grams of H2O are produced. In a separate experiment, the molar mass is found to be 132.1 g/mol. Determine the empirical formula and the molecular formula of the organic compound. **** Do the problem in Conversion factor style!
A 2.500-g sample of a hydrocarbon known to contain C, H, and O was burned in...
A 2.500-g sample of a hydrocarbon known to contain C, H, and O was burned in a C-H combustion train, producing 5.235 g of CO2 and 1.072 g of H2O. The molar mass of the compound is 126 g/mol. What is the molecular formula of the compound?
What is the empirical formula of a hydrocarbon if complete combustion or 5.400 mg of the...
What is the empirical formula of a hydrocarbon if complete combustion or 5.400 mg of the hydrocarbon produced 18.254 mg of CO2 and 3.736 mg of H2O? Be sure to write C first in the formula. empirical formula = What is the molecular formula if the molar mass of the hydrocarbon is found to be about 70 molecular formula =
5- Elemental analysis is sometimes carried out by combustion of the sample. For a hydrocarbon, the...
5- Elemental analysis is sometimes carried out by combustion of the sample. For a hydrocarbon, the only products formed are CO2 and H2O. If a 1.36-g sample of an unknown hydrocarbon is burned and 2.21 g of H2O are produced along with 4.07 g of CO2, what is the empirical formula of the hydrocarbon?
1.A 0.5538 g sample of a pure soluble bromide compound is dissolved in water, and all...
1.A 0.5538 g sample of a pure soluble bromide compound is dissolved in water, and all of the bromide ion is precipitated as AgBr by the addition of an excess of silver nitrate. The mass of the resulting AgBr is found to be 1.1298 g. What is the mass percentage of bromine in the original compound? % 2. A student determines the manganese(II) content of a solution by first precipitating it as manganese(II) hydroxide, and then decomposing the hydroxide to...