45.0 mL of 0.35 M NaOH is neutralized by 25 mL of an HCl solution. The molarity of the HCl solution is...
Balanced equation is
NaOH + HCl -----> NaCl + H2O
number of moles of NaOH = molarity of NaOh * volume of solution in L
number of moles of NaOH = 0.35*0.045 = 0.01575 mole
from the balanced equation we can say that
1 mole of NaOH requires 1 mole of HCl so
0.01575 mole of NaOH will require 0.01575 mole of HCl
molarity of HCl = number of moles of HCl / volume of solution in L
molarity of HCl = 0.01575 mole / 0.025 = 0.63 M
Therefore, the molarity of HCl = 0.63 M
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