Question

General question:

How do you find the pOH, given that the ionization is 10%?

Answer 1

The concentration in the whole explanation is in Molar units that is number of moles of solute per liter of solution.

Suppose the solution was treated with a base and its ionisation is given to be 10% then that means if the concentration of the base is given to be 'c'M. Then the concentration of the [OH^-] ions is 10% of c i.e. c*(10/100).

So now you have the cocentraion of [OH^-] ions with you that is c/10 M. So by the definition of pOH we have pOH = -log[OH^-] = -log[c/10].

Substituting the values of c will get you the required pOH of the solution. Further if you want to calculate the pH we have pH + pOH =14 .