Question

General question:

How do you find the pOH, given that the ionization is 10%?

Answer #1

The concentration in the whole explanation is in **Molar
units** that is number of moles of solute per liter of
solution.

Suppose the solution was treated with a base and its ionisation
is given to be 10% then that means if the concentration of the base
is given to be 'c'M. Then the concentration of the [OH^{-}]
ions is 10% of c i.e. c*(10/100).

So now you have the cocentraion of [OH^{-}] ions with
you that is c/10 M. So by the definition of pOH we have **pOH
= -log[OH ^{-}] = -log[c/10].**

**Substituting the values of c will get you the required
pOH of the solution**. Further if you want to calculate the
pH we have **pH + pOH =14** .

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