How do you find the pOH, given that the ionization is 10%?
The concentration in the whole explanation is in Molar units that is number of moles of solute per liter of solution.
Suppose the solution was treated with a base and its ionisation is given to be 10% then that means if the concentration of the base is given to be 'c'M. Then the concentration of the [OH-] ions is 10% of c i.e. c*(10/100).
So now you have the cocentraion of [OH-] ions with you that is c/10 M. So by the definition of pOH we have pOH = -log[OH-] = -log[c/10].
Substituting the values of c will get you the required pOH of the solution. Further if you want to calculate the pH we have pH + pOH =14 .
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