Question

When solutions of silver nitrate and calcium chloride are mixed, silver chloride precipitates out of solution...

When solutions of silver nitrate and calcium chloride are mixed, silver chloride precipitates out of solution according to the equation

2AgNO3(aq)+CaCl2(aq)→2AgCl(s)+Ca(NO3)2(aq)

Part A

What mass of silver chloride can be produced from 1.28 L of a 0.267 M solution of silver nitrate?

Express your answer with the appropriate units.

Part B

The reaction described in Part A required 3.60 L of calcium chloride. What is the concentration of this calcium chloride solution?

Express your answer with the appropriate units

Homework Answers

Answer #1

Part A

no. of mole = molarity volume of solution in liter

no. of mole of silver nitrate = 0.267 1.28 = 0.34176 mole

According to reaction 2 mole of silver nitrate produce 2 mole of silver chloride then 0.34176 mole of silver nitrate produce 0.34176 mole of silver chloride

molar mass of silver chloride = 143.32 gm / mole then 0.34176 mole of silver chloride = 143.32 0.34176 = 48.981 gm of silver chloride.

48.981 gm silver chloride produced.

Part B

According to reaction 2 mole of silver nitrate react with 1 mole of calcium chloride then to react with 0.34176 mole of silver nitrate required calcium chloride = 0.34176 / 2 = 0.17088 mole of calcium chloride

Molarity = no. of mole/volume of solution in liter

Molarity of calcium cloride = 0.17088 / 3.60 = 0.0475 M

Molarity of calcium cloride = 0.0475 M

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