Question

For a gaseous reaction, standard conditions are 298 K and a partial pressure of 1 atm...

For a gaseous reaction, standard conditions are 298 K and a partial pressure of 1 atm for all species. For the reaction N2(g)+3H2(g)==<>2NH3(g) the standard change in Gibbs free energy is Delta G=-72.6 kJ/mol. What is Delta G for this reaction at 298 K when the partial pressures are

P N2 = 0.200 atm, P H2 = 0.150 atm, and P NH3 = 0.900 atm

Homework Answers

Answer #1

    N2(g)+3H2(g)==<>2NH3(g)

   kp   = P2NH3/PN2 P3H2

         = (0.9)2/0.2*(0.15)3

            = 1200

G0   = -72.6KJ/mole = -72600J/mole

G   = G0 + RTlnKp

         = -72600+ 8.314*298*ln1200

          = -72600+ 2477.57*7.1

           = -55009.25J

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
For a gaseous reaction, standard conditions are 298 K and a partial pressure of 1 atm...
For a gaseous reaction, standard conditions are 298 K and a partial pressure of 1 atm for all species. For the reaction N2(g) + 3H2(g) <--> 2NH3 (g) the standard change in Gibbs free energy is ΔG° = -69.0 kJ/mol. What is ΔG for this reaction at 298 K when the partial pressures are PN2= 0.250 atm, PH2 = 0.450 atm, and PNH3 = 0.800 atm
For a gaseous reaction, standard conditions are 298 K and a partial pressure of 1 atm...
For a gaseous reaction, standard conditions are 298 K and a partial pressure of 1 atm for all species. For the reaction C2H6(g)+H2(g)↽−−⇀2CH4(g) the standard change in Gibbs free energy is Δ?°=−69.0 kJ/mol. What is ΔG for this reaction at 298 K when the partial pressures are ?C2H6=0.300 atm, ?H2=0.500 atm, and ?CH4=0.950 atm?
The chemical reaction N2(g) + 3H2(g) 2NH3(g) is carried out at 400. K. Assume the partial...
The chemical reaction N2(g) + 3H2(g) 2NH3(g) is carried out at 400. K. Assume the partial pressures of N2(g), H2(g), and NH3(g) are 1.0, 4.2, and 63 atm, respectively. The value of Kp = 54 at 700. K. for this reaction. (a) Calculate the reaction free energy. (b) Indicate whether this reaction mixture is likely to form reactants, is likely to form products, or is at equilibrium.
calculate the standard free energy change delta G for reaction N2 (g) +3H2(g)—>2NH3 N2 delta H=0.00kj...
calculate the standard free energy change delta G for reaction N2 (g) +3H2(g)—>2NH3 N2 delta H=0.00kj mol^-1s=+191.5J mol^-1K^-1 H2 delta H=0.00kj mol^-1,s = +130.6j mol^-1 k-1 NH3 delta H=-46.0kj mol^-1,s =192.5 J mol^-1 k-1 A. +112.3 kJ B.-87.6kJ C.-7.4kJ D.-32.9 kJ E.-151.1kJ
N2(g) + 3H2(g) -> 2NH3 (g) You charge a reaction vessel with 1.00 atm of all...
N2(g) + 3H2(g) -> 2NH3 (g) You charge a reaction vessel with 1.00 atm of all three gasses (N2,H2, and NH3) and allow them to come to equilibrium at 287K. you determine that 13.20% of the N2 gas has been consumed. what is delta G standard for this reaction based on these conditions?
In the Haber process, ammonia is synthesized from nitrogen and hydrogen: N2(g) + 3H2(g) → 2NH3(g)...
In the Haber process, ammonia is synthesized from nitrogen and hydrogen: N2(g) + 3H2(g) → 2NH3(g) ΔG° at 298 K for this reaction is -33.3 kJ/mol. The value of ΔG at 298 K for a reaction mixture that consists of 1.7 atm N2, 3.2 atm H2, and 0.85 atm NH3 is a) -139.6 b) 0.43 c) -4.63 × 103 d) -44.1 e) -1.08 × 104
The standard enthalpy change for this reaction is -731 kJ/mol at 298 K. 2 N2(g) +...
The standard enthalpy change for this reaction is -731 kJ/mol at 298 K. 2 N2(g) + 4 H2(g) + 3 O2(g) = 2 NH4NO3(s) ΔrH° = -731 kJ/mol Calculate the standard enthalpy change for the reaction N2(g) + 2 H2(g) + 3/2 O2(g) = NH4NO3(s) at 298 K.
4. Thermodynamic data for C(graphite) ​and C(​​diamond)​ at 298 K is given in the table below....
4. Thermodynamic data for C(graphite) ​and C(​​diamond)​ at 298 K is given in the table below. delta Hf​o ​(kJ/mol) o​ (J/mol K C​(graphite) 0.0 5.740 C​(diamond) 1.895 2.377 a) Calculate delta H​o​ and delta S​o and delta G​o ​for the transformation of 1 mole of graphite to diamond at 298 K. b) Is there a tempature at which this transformation will occur spontaneously at atmospheric pressure? Justify your answer. 8. Methanol can be made using the Fischer-Tropsch process according to...
Calculate the change in G for a reaction mixture that consists of 1 atm N2, 3atm...
Calculate the change in G for a reaction mixture that consists of 1 atm N2, 3atm H2, and .5 atm NH3 (N2 +3H2 2NH3)
1) For iodine gas [ I2(g) ], delta H= 62.4 kJ/mol and S = 260.7 J/mol-K....
1) For iodine gas [ I2(g) ], delta H= 62.4 kJ/mol and S = 260.7 J/mol-K. Calculate the equilibrium partial pressures of I2(g), H2(g), and HI(g) for the system 2HI(g) ⇌ H2(g) + I2(g) at 500oC if the initial partial pressures are all 0.200 atm.
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT