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What is the concentration of S2– in equilibrium with MnS(s) (Ksp = 4.6× 10–14) and 0.073...

What is the concentration of S2– in equilibrium with MnS(s) (Ksp = 4.6× 10–14) and 0.073 M Mn2 .

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Answer #1

MnS (s)   -------------->   Mn+2   +   S2-

                                         S             S

                                      0.073         S

Ksp = [Mn+2][S2-]

4.6 x 10^-14 = 0.073 x [S2-]

[S2-] = 6.3 x 10^-13 M

concentration of [S2-] = 6.3 x 10^-13 M

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