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Which has a standard enthalpy change equal to ΔHfo for glucose, C6H12O6?

Which has a standard enthalpy change equal to ΔHfo for glucose, C6H12O6?

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Answer #1

standard enthalpy formation : is defined as the change in enthalpy when one mole of a substance in the standard

state (1 atm of pressure and 298.15 K) is formed from its pure elements under the same conditions.

6 C (s) + 6 H2 (g) + 3 O2 (g) -------------> C6H12O6

ΔHfo = ΔHf products - reactants

        = ΔHf C6H12O6 - ( 6x ΔHf C+ 6 ΔHf H2 + 3 ΔHf O2 )

        = - 1273.3 - 0

ΔHfo = - 1273 kJ/mol

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