Question

Iron(III) oxide reacts with carbon to give iron and carbon monoxide.
Fe2O3(s)+3C(s)→2Fe(s)+3CO(g)

Part A: How many grams of C are required to react with 19.9 g of Fe2O3?

Part B: How many grams of CO are produced when 37.0 g of C reacts?

Part C: How many grams of Fe can be produced when 5.60 g of Fe2O3 reacts?

2. How many moles of S are in each of the following quantities?

Part A: 21 g of S (Express your answer using two significant figures.)

Part B: 124 g of SO2

Part C: 3.0 moles of Al2S3

Answer 1

Ans 1 :

Part A :

Number of moles of Fe2O3 = 19.9 / 159.7 = 0.125 mol

One mol of Fe2O3 needs 3 mol of C

so 0.125 mol of Fe2O3 will need : 3x 0.125

= 0.374 mol of C

Mass of C required = 0.374 x 12.01

= 4.49 grams

Part B :

Number of mol of C = 37.0 / 12.01 = 3.08 mol

So number of mol of CO produced will also be 3.08 mol

Mass of CO produced = 3.08 x 28.01

= 86.3 grams

Part C :

Number of mol of Fe2O3 = 5.60 / 159.7 = 0.035 mol

So number of mol of Fe produced = 2 x 0.035 = 0.07 mol

Mass of Fe produced = 0.07 x 55.845

= 3.92 grams