Iron(III) oxide reacts with carbon to give iron and carbon
Part A: How many grams of C are required to react with 19.9 g of Fe2O3?
Part B: How many grams of CO are produced when 37.0 g of C reacts?
Part C: How many grams of Fe can be produced when 5.60 g of Fe2O3 reacts?
2. How many moles of S are in each of the following quantities?
Part A: 21 g of S (Express your answer using two significant figures.)
Part B: 124 g of SO2
Part C: 3.0 moles of Al2S3
Ans 1 :
Part A :
Number of moles of Fe2O3 = 19.9 / 159.7 = 0.125 mol
One mol of Fe2O3 needs 3 mol of C
so 0.125 mol of Fe2O3 will need : 3x 0.125
= 0.374 mol of C
Mass of C required = 0.374 x 12.01
= 4.49 grams
Part B :
Number of mol of C = 37.0 / 12.01 = 3.08 mol
So number of mol of CO produced will also be 3.08 mol
Mass of CO produced = 3.08 x 28.01
= 86.3 grams
Part C :
Number of mol of Fe2O3 = 5.60 / 159.7 = 0.035 mol
So number of mol of Fe produced = 2 x 0.035 = 0.07 mol
Mass of Fe produced = 0.07 x 55.845
= 3.92 grams
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