Question

Mass of weigh boat	Mass of weigh boat + un-chewed gum	Mass of un-chewed gum	Mass of chewed gum	Mass of sugar	Percent of sugar
2.4g	8.5g	6.1g	4.7	1.4	22.95
2.4g	8.5g	6.1g	4.7	1.4	22.95
2.4g	8.5g	6.1g	4.7	1.4	22.95

Post-Lab Questions

1. What is the percent sugar? Show your calculations. (1.6/ 6.4)x100=22.95%

2. What is the molar mass of sugar C₁₂H₂₂O₁₁? Show your calculations.

C12H22O11 = 12(mass of C) + 22(mass of H) + 11(mass of O)

C12H22O11 = 12(12.01) + 22(1.008) + 11(16.00)

C12H22O11 = = 342.30

3. Convert the mass of dissolved sugar to moles. Show your calculations.

4. Convert the moles of sugar to molecules of sugar. Show your calculations.

5. Convert atoms of sugar to grams of sugar. Show your calculations.

6. Imagine that you used four pieces of gum instead of two. Calculate the number of moles. Show your calculations.

7. How does the mass of the saliva alter the experimental data?

Answer 1

Answer:

3) moles of sugar:

Weight of sugar = 1.4 g

molar mass of sugar = 342

moles = weight / molar mass

= 1.4 / 342

= 0.00409 moles.

4) molecules of sugar:

1 mole caotaines = 6.023 x 10²³ molecules

0.00409 = ?

= 0.00409 x 6.023 x10²³

= 0.0246 x 10²³

= 24 x 10²⁰ molecules

5)  Atoms of sugar to grams of sugar:

Sugar molecular formula =  C12H22O11

1 mole of sugar = 342 g

6.023 x 10²³ = 342

24 x 10²⁰ = ?

= 24 x 342 x 10²⁰ / 6.023 x10²³

= 8208 x 10²⁰ / 6.023 x 10²³

= 1362.77 x 10^-3

= 1.362 g

6) mass of gum = mass of unchewed gum - mass of chewed gum

= 6.1 - 4.7

= 1.4 g

Two pieces of gum weight = 1.4 g

Four pieces of gum weight = 1.4 x 2 = 2.8 g

7) The experimental data depends on the concentration of the sugar. The sugar concentration gradually decreases.