Question

A chunk of nickel weighing 19.7 grams and originally at 97.88 °C is dropped into an insulated cup containing 77.0 grams of water at 22.27 °C. Assuming that all of the heat is transferred to the water, the final temperature of the water is______ °C.

Answer #1

**specific heat capacity of nickel = 0.440
J/g.oC**

**specific heat capacity of water = 4.184
J/g.oC**

**Let us denote Ni by symbol 1 and H2O by symbol
2**

**m1 = 19.7 g**

**T1 = 97.88 oC**

**C1 = 0.44 J/goC**

**m2 = 77.0 g**

**T2 = 22.27 oC**

**C2 = 4.186 J/goC**

**T = to be calculated**

**Let the final temperature be T oC**

**use:**

**heat gained by 2 = heat lost by 1**

**m2*C2*(T-T2) = m1*C1*(T1-T)**

**77.0*4.186*(T-22.27) = 19.7*0.44*(97.88-T)**

**322.322*(T-22.27) = 8.668*(97.88-T)**

**322.322*T -7178.1109 = 848.4238 - 8.668*T)**

**T= 24.25 oC**

**Answer: 24.25 oC**

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